Andrew Stacey @mathforge.org · Mar 2

Thinking about the fact that the link between determinants and area is on the spec so, despite my misgivings, I have to cover it. So here's an approach I don't fully loathe ... Area of parallelogram is area of blue rectangle minus area of red. Proof: tessellation. #ALevelMaths #mathsky

21 likes 9 replies

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Replies

Cubes_Art · Mar 2

Here’s an applet my colleagues and I designed for supporting ways of reasoning about determinants as a signed ratio of the area of a pre-image to the area of its image. www.geogebra.org/m/v8hw88fs

Catriona Agg · Mar 2

Whoa 🤯

Joshua Grochow · Mar 2

This is an awesome visual proof! (that I hadn't seen before) Also has me thinking about deriving det using inclusion-exclusion. Bc apparently that really is the source of all signs...

Sheena · Mar 2

I really really like this. I've not seen it before

Susan Whitehouse · Mar 4

Is it obvious that, because the unit square maps to a parallelogram of area ad-bc, the transformation will have the same scaling effect on every area?(Not to me, clearly, but should it be?)

Susan Whitehouse · Mar 4

I love this and I can see the temptation to find rectangles bc and ad on the diagram, but I find the tessellation difficult to get my head around and those two rectangles don't give me any insight. I would prefer to go for the big rectangle around the parallelogram and subtract the extra bits.

New lettuce · Mar 3

That's fun

Bill Wood · Mar 2

Why the misgivings?

David K Butler · Mar 4

Are you able to give me some more words/pictures to explain how the tesselation explains the area is the difference between the rectangles? Because I just can’t see it.